# Help with turning a fraction into a exponent

• Mar 3rd 2009, 08:24 PM
ckylek
Help with turning a fraction into a exponent
hey everybody, i hope im posting this in the right place but i am trying to figure out how to turn :

(u+1)/2 into an exponent of u so i can multiply it by u^(1/2)

total problem:

((u+1)/2)*(u^(1/2))

Any help at all would be awesome and thanks!
• Mar 3rd 2009, 08:26 PM
mollymcf2009
Quote:

Originally Posted by ckylek
hey everybody, i hope im posting this in the right place but i am trying to figure out how to turn :

(u+1)/2 into an exponent of u so i can multiply it by u^(1/2)

total problem:

((u+1)/2)*(u^(1/2))

Any help at all would be awesome and thanks!

$\displaystyle u^\frac{1}{2} = \sqrt u$

• Mar 3rd 2009, 08:32 PM
ckylek
sorry
Quote:

Originally Posted by mollymcf2009
$\displaystyle u^\frac{1}{2} = \sqrt u$

hey sorry i wasn 't really clear with my question. my problem wasnt really with
u^(1/2) it was with how to turn (u+1)/2 into a exponent so i can do the rest of the problem. Im studying this for a cal II college midterm tomorrow but i dont think this is really a calculus question, i think its more algebra....not sure tho.

• Mar 3rd 2009, 08:41 PM
mollymcf2009
Quote:

Originally Posted by ckylek
hey sorry i wasn 't really clear with my question. my problem wasnt really with
u^(1/2) it was with how to turn (u+1)/2 into a exponent so i can do the rest of the problem. Im studying this for a cal II college midterm tomorrow but i dont think this is really a calculus question, i think its more algebra....not sure tho.

Ok, so could you not multiply through using the $\displaystyle \sqrt u$ ?

I mean, I guess you could do this:

$\displaystyle (u+1) \cdot 2^{-1}$ that's about it though
• Mar 3rd 2009, 08:51 PM
ckylek
Quote:

Originally Posted by mollymcf2009
Ok, so could you not multiply through using the $\displaystyle \sqrt u$ ?

I mean, I guess you could do this:

$\displaystyle (u+1) \cdot 2^{-1}$ that's about it though

Yeah! Actually that works great for the purposes of getting u. I guess I was thinking about it the wrong way but what you suggested works great! Thank You!!

....back to studying