Thread: Basic algebra

1) 1=12+n

2) 3=-5-10x

3) 4=5/3n

4) 8^-1/y +3^-1=-3

5) 10c=-3-3c

6) 6=-10-5m

7) 11=y/2^-1 -7

8) 10/11=3-8y+8

9) 5=60n^-1 -1

10) 4/8=10n/6

Originally Posted by jerryramos

1) 1=12+n

Subtract 12 from both sides to get:

Try the other ones, and then tell me what ones you need help on...

Originally Posted by jerryramos

1) 1=12+n

2) 3=-5-10x

3) 4=5/3n

4) 8^-1/y +3^-1=-3

5) 10c=-3-3c

6) 6=-10-5m

7) 11=y/2^-1 -7

8) 10/11=3-8y+8

9) 5=60n^-1 -1

10) 4/8=10n/6

2) 3=-5-10x

5 + 3 = 5 + -5-10x

8 = -10x





-Dan

Originally Posted by jerryramos

3) 4=5/3n

-Dan

Originally Posted by jerryramos

4) 8^-1/y +3^-1=-3

Note that [tex]a^{-1} = \frac{1}{a}[tex] ( .)

So






Let's get rid of these pesky fractions, shall we? The least common multiple of 3 and 8 is 24, so multiply both sides of the equation by 24:

















-Dan