1) 1=12+n 2) 3=-5-10x 3) 4=5/3n 4) 8^-1/y +3^-1=-3 5) 10c=-3-3c 6) 6=-10-5m 7) 11=y/2^-1 -7 8) 10/11=3-8y+8 9) 5=60n^-1 -1 10) 4/8=10n/6
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Originally Posted by jerryramos 1) 1=12+n Subtract 12 from both sides to get: Try the other ones, and then tell me what ones you need help on...
Originally Posted by jerryramos 1) 1=12+n 2) 3=-5-10x 3) 4=5/3n 4) 8^-1/y +3^-1=-3 5) 10c=-3-3c 6) 6=-10-5m 7) 11=y/2^-1 -7 8) 10/11=3-8y+8 9) 5=60n^-1 -1 10) 4/8=10n/6 2) 3=-5-10x 5 + 3 = 5 + -5-10x 8 = -10x -Dan
Originally Posted by jerryramos 3) 4=5/3n -Dan
Originally Posted by jerryramos 4) 8^-1/y +3^-1=-3 Note that [tex]a^{-1} = \frac{1}{a}[tex] ( .) So Let's get rid of these pesky fractions, shall we? The least common multiple of 3 and 8 is 24, so multiply both sides of the equation by 24: -Dan
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