# Antilogs!

• Mar 3rd 2009, 02:03 PM
puzzledwithpolynomials
Antilogs!
How can I evaluate:
Anti-log (-0.06) = x
Anti-log (0.03012) = x
• Mar 3rd 2009, 02:12 PM
skeeter
Quote:

Originally Posted by puzzledwithpolynomials
How can I evaluate:
Anti-log (-0.06) = x
Anti-log (0.03012) = x

assuming base 10 ...

\$\displaystyle x = 10^{-0.06}\$

\$\displaystyle x = 10^{0.03012}\$

• Mar 3rd 2009, 02:15 PM
puzzledwithpolynomials
Oh, that's what I had - I didn't think that was all! :P Thank you!
• Mar 3rd 2009, 02:20 PM
masters
Quote:

Originally Posted by puzzledwithpolynomials
How can I evaluate:
Anti-log (-0.06) = x
Anti-log (0.03012) = x

Hi puzzled,

Are you using a calculator or tables? Calculator, I hope.

The antilogarithm function is another name for the inverse of the logarithmic function. It is written \$\displaystyle antilog_b(n)\$ and means the same as \$\displaystyle b^n\$.

Example:

\$\displaystyle log_{10} 100 = 2\$

\$\displaystyle antilog (2) = 10^2\$

So,

\$\displaystyle antilog (-0.06)=10^{-0.06}\$

\$\displaystyle antilog (0.03012)=10^{0.03012}\$

Edit: And as always, Skeeter gets it done in fewer words!