f (x) = (x − a)3 + (x − b)3 + (x − c)3 , a < b < c. The number of real roots of f (x) = 0 is (A) 3; (B) 2; (C) 1; (D) 0. Please guide me with this question..
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f has at least one real root. f is strictly increasing, so f is injective. Therefore, f has only one real root.
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