Thread: infinite surd problem

hey....i need some help...all i need to know is where does or how does
b= 2c+ 1 in the following part of a question in a thread posted on infinite surds in this forum. Any help would be appreciated. Thx

Originally Posted by Soroban

Hello, starvin-marvin!


We have: ., for some integer

. . Then: .

We see that:


Let: ------ Where does this come from ?

Then [1] becomes: .

Hence, must be the product of two consecutive integers.


Then: ., an integer.

any number of the form (2c+1) is an odd number.

now,b is a variable odd number & thus for any integral value of c,u get the values of b accordingly.

Originally Posted by sbcd90

any number of the form (2c+1) is an odd number.

and, conversely, any odd number is of the form 2c+ 1 for some integer c?

[quot]now,b is a variable odd number & thus for any integral value of c,u get the values of b accordingly.[/QUOTE]

Thx, however, another question is that..why do we have to apply the formula to deduce the k= the product of two consective integers? is there a reason or antoher way? Thx for the replies

nevermind guys...i found the answer to my own question! thx for all your help

Yes, I agree.

Originally Posted by moe23

hey....i need some help...all i need to know is where does or how does
b= 2c+ 1 in the following part of a question in a thread posted on infinite surds in this forum. Any help would be appreciated. Thx

This quote was taken from a thread that was closed because the question was part of an IB portfolio assessment. I can only assume you have asked your question in a new thread because you are doing the same assessment ans were trying to conceal this fact.

Thread closed.