1. ## Ratio problem.

I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?

The teacher didn't explain very well, so I've come here. If I try it out, I get

x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.

2. Originally Posted by Auburn
I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?

The teacher didn't explain very well, so I've come here. If I try it out, I get

x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.
You did not distribute correctly.

$\displaystyle \frac x2=\frac5{x+3}$

$\displaystyle \Rightarrow x(x+3)=5\cdot2$

$\displaystyle \Rightarrow x^2+3x=10$

$\displaystyle \Rightarrow x^2+3x-10=0$

This is easily factored.

3. Originally Posted by Auburn
I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?

The teacher didn't explain very well, so I've come here. If I try it out, I get

x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.
Actually if you cross multiply, you would get

$\displaystyle x^2 + 3x = 10$

So,

$\displaystyle x^2 + 3x -10 = 0$

Can you take it from here?

4. Oh I see, whoops. Thanks man.