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Math Help - Ratio problem.

  1. #1
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    Ratio problem.

    I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?



    The teacher didn't explain very well, so I've come here. If I try it out, I get

    x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.
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  2. #2
    MHF Contributor Reckoner's Avatar
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    Quote Originally Posted by Auburn View Post
    I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?



    The teacher didn't explain very well, so I've come here. If I try it out, I get

    x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.
    You did not distribute correctly.

    \frac x2=\frac5{x+3}

    \Rightarrow x(x+3)=5\cdot2

    \Rightarrow x^2+3x=10

    \Rightarrow x^2+3x-10=0

    This is easily factored.
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  3. #3
    Senior Member mollymcf2009's Avatar
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    Quote Originally Posted by Auburn View Post
    I hate to bump for such a simple problem, but could someone please enlighten me on how to do this problem?



    The teacher didn't explain very well, so I've come here. If I try it out, I get

    x^2 + 3 = 10 so then x^2 = 7. That didn't work out, so if anyone could spare a little time to help that would be amazing.
    Actually if you cross multiply, you would get

    x^2 + 3x = 10

    So,

    x^2 + 3x -10 = 0

    Can you take it from here?
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  4. #4
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    Oh I see, whoops. Thanks man.
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