The general motion equation is given by:
d(t)=1/2 gt^2+v_ot +d_o where:
d(t) is the distance traveled, in metres
g is the acceleration due to gravity in m/s2
t is the time, in seconds (s)
vo is the initial velocity of the moving object
do is the initial height in metres.
An object is dropped from a height of 1,000 m, on Mars, where the acceleration due to gravity is 3.92 m/s2. Find, to two decimal places, the time it will take for the object to hit the surface of Mars.
i get 1.96t^2, is it right?
Hello, William!
Their formula isn't accurate . . .
They should have explained about "upward is positive", etc.
The general motion equation is given by: . where:
is the distance traveled, in metres
is the acceleration due to gravity in m/sē
is the time, in seconds,
is the initial velocity of the moving object,
is the initial height in metres.
An object is dropped from a height of 1,000 m, on Mars,
where the acceleration due to gravity is 3.92 m/sē.
Find, to two decimal places, the time it will take for the object to hit the surface of Mars.
i get 1.96t^2 . . . . You have a in there?
We are given: .
. . The equation is: .
"Hit the surface" means
. . Therefore: .