Apparently $\displaystyle \frac{1}{28}(2x-1)^7 + \frac{1}{24}(2x-1)^6 = \frac{1}{168}(2x-1)^6(12x+1)$ I can't see it, I'd appreciate some help.

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- Mar 2nd 2009, 12:19 PMJeWiShalgebra simplify
Apparently $\displaystyle \frac{1}{28}(2x-1)^7 + \frac{1}{24}(2x-1)^6 = \frac{1}{168}(2x-1)^6(12x+1)$ I can't see it, I'd appreciate some help.

- Mar 2nd 2009, 12:40 PMProve It
- Mar 2nd 2009, 01:23 PMJeWiSh