# algebra simplify

• Mar 2nd 2009, 12:19 PM
JeWiSh
algebra simplify
Apparently $\frac{1}{28}(2x-1)^7 + \frac{1}{24}(2x-1)^6 = \frac{1}{168}(2x-1)^6(12x+1)$ I can't see it, I'd appreciate some help.
• Mar 2nd 2009, 12:40 PM
Prove It
Quote:

Originally Posted by JeWiSh
Apparently $\frac{1}{28}(2x-1)^7 + \frac{1}{24}(2x-1)^6 = \frac{1}{168}(2x-1)^6(12x+1)$ I can't see it, I'd appreciate some help.

Take out a common factor of $(2x - 1)^6$.

This gives

$(2x - 1)^6\left[\frac{1}{28}(2x - 1) + \frac{1}{24}\right]$

Can you go from there?
• Mar 2nd 2009, 01:23 PM
JeWiSh
Quote:

Originally Posted by Prove It
Take out a common factor of $(2x - 1)^6$.

This gives

$(2x - 1)^6\left[\frac{1}{28}(2x - 1) + \frac{1}{24}\right]$

Can you go from there?

Ahhh, yes got it, thanks.