ahh thanks! umm i actually have two more questions (sorry!)

um a) caculate the x and y intercept of the staright line with the equation 3x-2y=9

and

b) transpose the equation 3y+7=5x+4 into y=mx+c form.

2. ## y=mx+c

Originally Posted by coldplayroxs
ahh thanks! umm i actually have two more questions (sorry!)

um a) caculate the x and y intercept of the staright line with the equation 3x-2y=9

and

b) transpose the equation 3y+7=5x+4 into y=mx+c form.
a) $3x-9=2y$; at x-intercept $y=0$;
so $3x-9=0$ & $x=3$
At y-intercept $x=0$ so $-9=2y$ & $y=-9/2$

b) $3y+3=5x$ & $y=5x/3 - 1$

3. Originally Posted by coldplayroxs
ahh thanks! umm i actually have two more questions (sorry!)

um a) caculate the x and y intercept of the staright line with the equation 3x-2y=9

and

b) transpose the equation 3y+7=5x+4 into y=mx+c form.
Whenever you have a line and you want to find the x & y intercepts, you can plug zero in for y to solve for the x intercept (which is where y would equal zero) and zero in for x to find the y intercept.

For part b, just solve for y. This is simple algebra:

$3y + 7 = 5x + 4$

$3y = 5x - 3$

$y = \frac{5}{3}x - 1$