
Natural log problem
I've solved this problem a couple different ways and come up with different answers and I have had a couple other people come up with different answers. What log basic am I missing?
Given that ln a = 5 and ln b = 7 evaluate the following:
ln a2 be2

Is it
$\displaystyle \ln a^2 \ln be^2$
or
$\displaystyle \ln a^2 \ln (be)^2$
Assuming its $\displaystyle \ln a^2 \ln be^2$
= 2\ln a ( \ln b + 2\ln e)
= 2\ln a ( \ln b +2)
2 x 5 ( 7 + 2)
2 x 5 x 9
90

Problem is presented as:
ln a^2be^2 no spaces between variables

then its
$\displaystyle \n a^2be^2 $
$\displaystyle = \ln a^2 + \ln b + \ln e^2$
$\displaystyle = 2\ln a + \ln b + 2\ln e$
= 2 x 5 + 7 + 2 x 1
= 19