Pair of weight in ascending order are

292, 295, 381, 383, 386, 388, 391, 391, 397, 402

Let weight of 5 hipos in ascending order be a, b,c,d and e

i.e

a<b<c<d<e

Now a+b+c+d+e =one fourth of sum of all 10 weights given above (think why )

so a+b+c+d+e = 3706/4 = 926.5

But question says that all weight are in whole number.

So you have made a mistake in typing the pair of weights.

Anyways.

let me give you a brief approach to solve this problem.

From above we have a+b+c+d+e.

Now a+b = 292 (since a and b are two lowest weights, their sum will be the lowest paired weight

d+e = 402 (since d and e are largest, their sum is largest)

so we get a+b+d+e = 694

so c can be found out

c = 926.5 - 694 = 232.5

Now second highest sum 397 should be of pair e and c

so e + c = 397

so e = 397 - 232.5 = 164.5 which is less than c

so we can see that numbers are all messed up

But now you have an idea of approach to solve this question.

If you can re check your question and give me right numbers, I can provide complete solution.