solve the equation for x:
ln x + ln (x-3) = 0
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Originally Posted by algebra2 solve the equation for x:
ln x + ln (x-3) = 0 use the product property of logs ...
change to an exponential equation ...
solve the quadratic equation ... remember that only values of x > 3 are valid.
ln(x) +l(x-3) =0
x(x-3) = e^0
x^2 - 3x -1=0 (Use the quadratic formula to find the roots)
Last edited by CaptainBlack; March 1st 2009 at 10:35 AM.
Reason: removed the last steps, so that the OP has the opertunity to do some of the work
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