# polynomial descending order

• Feb 27th 2009, 03:59 PM
william
polynomial descending order
\$\displaystyle x^5+5x+2x^3+3x^2+4x^4+6\$ in descending order is:

\$\displaystyle a)x^5+4x^4+2x^3+5x+6\$

\$\displaystyle b)6+5x+3x^3+2x^3+4x^4+x^5\$

\$\displaystyle
c) none of the above( my choice )\$

d) \$\displaystyle -(6+5x+3x^2+2x^3+4x^4+x^5)\$
• Feb 27th 2009, 04:02 PM
e^(i*pi)
Quote:

Originally Posted by william
\$\displaystyle x^5+5x+2x^3+3x^2+4x^4+6\$ in descending order is:

\$\displaystyle a)x^5+4x^4+2x^3+5x+6\$

\$\displaystyle b)6+5x+3x^3+2x^3+4x^4+x^5\$

\$\displaystyle
c) none of the above( my choice )\$

d) \$\displaystyle -(6+5x+3x^2+2x^3+4x^4+x^5)\$

\$\displaystyle x^5 + 4x^4 + 2x^3 + 5x + 6 \$ which is answer C
• Feb 27th 2009, 04:06 PM
william
Quote:

Originally Posted by e^(i*pi)
\$\displaystyle x^5 + 4x^4 + 2x^3 + 5x + 6 \$ which is answer C

Thanks,What you have put is choice a), how can that be if there is a term missing?
• Feb 27th 2009, 04:17 PM
e^(i*pi)
Quote:

Originally Posted by william
Thanks,What you have put is choice a), how can that be if there is a term missing?

That was me misreading option A (Doh)
I edited my post to option C upon realising this