Can you please help me to simplify this-
6p^2q/9q^2r times 2pr/5pq divide by 8rqp/6r^3p^2
Many thanks to all benevolences!
Note that
$\displaystyle a^ma^n = a^{m+n}$
$\displaystyle a^m/a^n = a^{m-n}$
In your case we have
$\displaystyle (6p^2q)(2pr/5pq)/(8rqp/[6r^3p^2])$
when dividing by a fraction we may flip it and multiply:
$\displaystyle (6p^2q)(2pr/5pq)(6r^3p^2)/(8rqp)$
to which we collect and simplify, one at a time to get :
$\displaystyle \frac{9}{5}p^4q^{-1}r^3$ = $\displaystyle \frac{9p^4r^3}{5q}$