# Thread: Exponents power to a power

1. ## Exponents power to a power

Wondering if someone can check my work, thanks!

(5x^3y^2)^3
I got 125x^9y^6

(3ab^5)^2(a^4b^6)
I got 9a^6b^16

(-2fg^2h^7)^4
I got -16f^4g^8h^28

(3xy)^3(4x^5y^2)^2
I got 432x^13y^4

Also was wondering if anyone can help me with this probelm
-(4x)^3(2x)^2(x^5)^5

2. Originally Posted by Jubbly
Wondering if someone can check my work, thanks!

(5x^3y^2)^3
I got 125x^9y^6
correct

(3ab^5)^2(a^4b^6)
I got 9a^6b^16
correct

(-2fg^2h^7)^4
I got -16f^4g^8h^28
$\displaystyle (-1)4= 1$ not -1.

(3xy)^3(4x^5y^2)^2
I got 432x^13y^4
You forgot the first $\displaystyle y^3$

Also was wondering if anyone can help me with this probelm
-(4x)^3(2x)^2(x^5)^5
$\displaystyle 4^3= 64$, $\displaystyle 2^2= 4$ and 64(4)= 256. $\displaystyle (x^3)(x^2)(x^5)= x^{3+ 2+ 5}= x^{10}$. And notice that the "-" is outside any power.

3. Uhm.. for this equation (-2fg^2h^7)^4
I don't understand you, other than that thanks for helping!
Also for the last one since the negative is outside will the numbers still be negative?

4. Originally Posted by Jubbly
Uhm.. for this equation (-2fg^2h^7)^4
I don't understand you, other than that thanks for helping!
(-1)^4 = 1 .....sign is inside bracket else you are correct

Also for the last one since the negative is outside will the numbers still be negative?
Yes you are correct