I can't figure out how to solve this for x 13 + log2 x^(-3) = -22 this apparently simplifies to x = 2^(35/3) could somebody please tell me how to solve this one? thankyou
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Is the equation $\displaystyle 13 + log(2) x^{-3}=-22 $ or $\displaystyle 13 + log(2x^{-3})=-22 $?
Originally Posted by maths_cat I can't figure out how to solve this for x 13 + log2 x^(-3) = -22 this apparently simplifies to x = 2^(35/3) could somebody please tell me how to solve this one? thankyou Hi maths_cat, Just use a few simple log rules to get: $\displaystyle 13+\log_2 x^{-3}=-22$ $\displaystyle -3\log_2 x=-35$ $\displaystyle \log_2 x=\frac{35}{3}$ $\displaystyle x = 2^{\frac{35}{3}}$
thanks for the help guys!
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