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Math Help - Another Binomial theorem

  1. #1
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    Another Binomial theorem

    By assuming 0<\sqrt{5}-2<\frac{1}{4} , deduce that the difference between (\sqrt{5}+2)^5 and an integer is less than \frac{1}{1024}
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  2. #2
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    Quote Originally Posted by thereddevils View Post
    By assuming 0<\sqrt{5}-2<\frac{1}{4} , deduce that the difference between (\sqrt{5}+2)^5 and an integer is less than \frac{1}{1024}

    These are what i can think of :

    0+4<\sqrt{5}-2+4<\frac{1}{4}+4

    4<\sqrt{5}+2<\frac{5}{4}

     4^5<(\sqrt{5}+2)^5<(\frac{17}{4})^5

    BUt i still don see the solution to these question .
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