Required a mathematical solution of the problem
Hello Friend .............
Here is a problem stated as:
Let there is a milkman who requires 40 liter of milk a day. constraint is that he can have exactly 19 animals. and the animals he can choose are as below with their capability of giving milk.
Cow can give 2 liters a day.
Buffalo can give 5 liters a day. and
Goat can give (1/4) liter a day.
This problem's solution is:
No of Cows =12 milk produced = 12 * 2 = 24
No of Buffaloes = 3 milk produced = 5*3 = 15
No of Goats = 4 milk produced =(1/4) * 4 = 1
No of animals =19 milk produced =40 liters
Now Problem is that is there any system of liner equations that can be used to get answer of such type of problems, Trial and error methods is not needed.
Thank you all........