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Thread: [SOLVED] equation of line

  1. #1
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    [SOLVED] equation of line

    Find an equation for the line with the given properties.

    Perpendicular to the line y=1/3x + 6; containing the point (2,-2)
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  2. #2
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    Quote Originally Posted by Ashley189 View Post
    Find an equation for the line with the given properties.

    Perpendicular to the line y=1/3x + 6; containing the point (2,-2)
    would have slope:

    m=-3

    (a, b)=(2, -2)

    so

    y+2=-3(x-2) from y-b=m(x-a).

    \Box
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  3. #3
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    Quote Originally Posted by GaloisTheory1 View Post
    would have slope:

    m=-3

    (a, b)=(2, -2)

    so

    y+2=-3(x-2) from y-b=m(x-a).

    \Box
    I get it a little bit, but I'm still kinda confused.
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  4. #4
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    Quote Originally Posted by Ashley189 View Post
    Find an equation for the line with the given properties.

    Perpendicular to the line y=1/3x + 6; containing the point (2,-2)

    You know the line is perpendicular to y=1/3x+6 so we can find its gradient .

    using the formula m_1m_2=-1 , we find that its gradient is -3.

    This line passes through point (2,-2)

    Using this formula , y-y_1=m(x-x_1)

    Substitute appropriately , we get y-(-2)=-3(x-2) and simplify it ,
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