Find an equation for the line with the given properties.
Perpendicular to the line y=1/3x + 6; containing the point (2,-2)
You know the line is perpendicular to y=1/3x+6 so we can find its gradient .
using the formula $\displaystyle m_1m_2=-1$ , we find that its gradient is -3.
This line passes through point (2,-2)
Using this formula , $\displaystyle y-y_1=m(x-x_1)$
Substitute appropriately , we get $\displaystyle y-(-2)=-3(x-2)$ and simplify it ,