# Thread: [SOLVED] Whole consecutive numbers

1. ## [SOLVED] Whole consecutive numbers

The problem states:

Find 4 consecutive whole numbers such that the sum of the first three numbers equals the fourth number.

Ok, so heres how I think it should be:

x = 1st #
x+1 = 2nd #
x+2 = 3rd #
x+3 = 4th #

(x) + (x+1) + (x+2) = (x+3)

Now if this is correct then this is how it works out...

3x+3=x+3
2x+3=3
2x=0

Now this is where Im stumped. Any help would be appreciated.

2. Find 4 consecutive whole numbers such that the sum of the first three numbers equals the fourth number.

set of whole numbers is {0, 1, 2, 3, ... }

0+1+2 = 3

works for me.

3. Yes, I agree those are the numbers, but I need to show work. I cant figure out how the equation works out. Or is my work correct. THANKS

4. Yes your equation is correct.
$2x = 0$
means $x = 0$

and we have assumed that numbers are $x, x + 1, x + 2, x + 3$
so numbers are 0, 0+1,0+2,1+3
i.e. 0, 1, 2 and 3.

5. WONDERFUL!

I certainly surpised myself. THANKS

6. Originally Posted by seders99
WONDERFUL!

I certainly surpised myself. THANKS
Most of the time, if you follow basics correctly, problems will be solved easily. Maths is very rational subject.

Keep Walking Bro.