V = g t
=> dx = gt dt
Integrate both sides:
x = (1/2) g t^2
Is this what you want ?
Although energy equations can be used to prove the velocity of any mass in free fall, this there a method to prove the free fall of any mass in a time period.
by example; t = square root 2s/g but this method does not include either the energy of the mass, or the mass in question.
what I am therefore asking is does anyone know of a method to include the mass or energy into a equation or formula to find the time of any mass in free fall, neglecting air resistance.
After falling a distance of s body of mass m loses potential energy equalt to
Gain in kinetic velocity
By law of conservation of evergy, loss in potential enrgy equals gain in kinetix energy
Hope you are looking for the same.
Also if you assume that mass has initial velocity, the just use change of kinetic energy equal to change in potential energy. So this will introduce the quantity initial velocity in the equation.
Your sentense "Although energy equations ..." is misleading. I thought you don't want to use Energy conservation. Anyways, arpitagarwal82's approach is correct.
dx/dt = sqrt(2gx)
dx/sqrt(x) = sqrt(2g) dt
integrate both sides and you'll get:
The same result.
by example, any mass in free fall neglecting air resistance could be found by t = sqrt 2s/g. But that equation does not include the mass, so could relate to just about anything if you see what i mean?
David, I think we're having some kind of communication problem here. Physical experiments show that objects in the vacuum -regardless of their mass- accelarates the same parameter towards center of the earth. That's what Newton observed and claimed. That is:
F=G m1 m2 / d^2
G is a universal constant
m1, m2 are masses,
d is the distance between masses.
Let m1 be the mass of Earth, and d is approx. it's radius, R, then:
F = m2 * a = G m1 m2 / R^2
m2's will cancel out. AND THAT'S WHY mass of the object has no effect. You'll have:
a = G m1 / R^2 all constants for Earth.
a here is called as g, and almost constant all over the world, about 9.8 m/s^2.
Objects regardless of their mass accelerates about 9.8 m/s for every passing second towards the center of Earth.
No, Earth is not flat!
The Earth is a Sphere, the acceleration due to gravity at the equator is 9.78 ms^2, and at other locations 9.81 ms^2.
The original question asked for a equation or formula to show any individual mass in free fall, it is therefore safe to say then that only controlled experiments would prove each mass in free fall, and there is no mathematical way of proof.