$\displaystyle 4n^{3/2} = 8^{-1/3}$

Find the value of n

hi all, ive been given the above and need to solve it without a calculator. ive expessed it in all the indice rules but cant come up with a suitable format to solve it.

any ideas?

here's what i got so far $\displaystyle n^{3/2} = \frac{1}{8}$

so does $\displaystyle n = \sqrt[{3/2}]{1/8}$

thanks for the model answer ADARSH and help with formatting

$\displaystyle (n^{3/2})^{2/3}=(2^{-3})^{2/3}$

therefore

$\displaystyle n=2^{-2}$

therefore

$\displaystyle n=\frac{1}{2^2}$