q)$\displaystyle \frac{27c^2}{16a^2b}.\frac{100ac}{63b^2}.\frac{7ab }{15c} $ Thank you....
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$\displaystyle = \frac{ (3)^3\times 2^2 5^2 \times 7 \times c^3 a^2 b}{4^2 \times 7.9\times 5.3\times b^3 a^2 c} $ $\displaystyle = \frac{ 5 \times c^2 }{4 \times b^2 } $
Originally Posted by ADARSH $\displaystyle = \frac{ (3)^3\times 2^2 5^2 \times 7 \times c^3 a^2 b}{4^2 \times 7.9\times 5.3\times b^3 a^2 c} $ $\displaystyle = \frac{ 5 \times c^2 }{4 \times b^2 } $ Thank's for your help ...
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