How could this be simplified in summation notation:

5 * y1 + 25 * y2 + 125 * y3

Thanks!

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- Feb 23rd 2009, 09:40 PMgenkislawSummation Notation Problem
How could this be simplified in summation notation:

5 * y1 + 25 * y2 + 125 * y3

Thanks! - Feb 23rd 2009, 09:47 PMADARSH
Welcome to the forum (Party)

$\displaystyle 5 \times y^1 + 25 \times y^2 + 125 \times y^3$

$\displaystyle (5\times y)^1 +(5\times y)^2 + (5\times y)^ 3$

$\displaystyle

\sum_{r= 1}^{3}{(5\times y)^r}

$ - Feb 23rd 2009, 09:50 PMgenkislaw
Thanks, ADARSH.

What about this, if I was putting it in summation notation using sigma?

4 * x(sub)i + 4 * x(sub)i^2 + 4 * x(sub)i^3 + 4 * x(sub)i^4

Thanks! - Feb 23rd 2009, 09:55 PMADARSH
$\displaystyle 4 \times \xi + 4 \times \xi^2 + 4 \times \xi^3 + 4 \times \xi^4$

$\displaystyle = 4( \xi + \xi^2 + \xi^3 + \xi^4)$

$\displaystyle = 4 \sum_{r=1}^{4}{\xi}^r.....\text{I can't really understand x(sub)i but you can put it in place of }\xi $

Guess : I think you mean x_i ...if its so then your answer is

$\displaystyle ~ =~ 4 \sum_{r=1}^{4}{x_i}^r$ - Feb 23rd 2009, 10:17 PMgenkislaw
Thanks!