General rule when having number raised by negative number is:
I will show you examples from your equations for such numbers but you should try to do all this by yourself since you have been given help from Soroban and me for similar examples.
So we have
Notice that we only raised x by -1 not 3x.
You have also .
Notice that we raised 3a by -1 not just a.
Try to do something and this forum will help you in your effort.
uhm... i'm not sure here's my answer:
1.) (3/x -2/y)/(2/y-3/x) = {3(y)-2(x)/xy} = (3y-2x/xy)/(2x-3y/xy)= (3y-2x/xy) * (xy/2x-3y)=////////// (3y-2x)/(2x-3y)final answer
2.) (1/3a-1/2b)/(1/2b+1/3a) = {2b-3a/(3a)(2b)}/{(3a+2b/(2b)(3a)}={2b-3a/(3a)(2b)}*{3a+2b/(2b)(3a)}= ////////-3a/3a,,, final answer
3.) (1/ab+1/ba)/(1/ab)= (1/ab)/(1/ab)= (1/ab*ab/1)=///////////1,,, final answer
hehe i'm not sure
1) Correct.
2) Answer is not correct. You have done it almost ok but at the end you made an error.
Solution is:
can't be further simplifed as you did to
3) Not correct. You made a mistake at start.
It's not because only b is raised by -1. If it were then it would be .
Correct is .
Now, try to do 3) again.