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Math Help - Finding Solutions?

  1. #1
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    Finding Solutions?

    5x^2+28x-49

    What are the solutions? and how do I find them
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  2. #2
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    Quote Originally Posted by greenpumpkins View Post
    5x^2+28x-49

    What are the solutions? and how do I find them
    There is no equation => no solution

    If the equation is 5x^2+28x-49=0 then you can use the formula

    x = \frac{-14 \pm 21}{5}

    x_1 = -7 and x_2 = \frac{7}{5}
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  3. #3
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    Quote Originally Posted by running-gag View Post
    There is no equation => no solution

    If the equation is 5x^2+28x-49=0 then you can use the formula

    x = \frac{-14 \pm 21}{5}

    x_1 = -7 and x_2 = \frac{7}{5}
    Uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly NOT 0!
    Where did you get that formula?
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  4. #4
    Behold, the power of SARDINES!
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    Quote Originally Posted by hallsofivy View Post
    uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly not 0!
    Where did you get that formula?
    5(49)+28(-7)-49= 245-196-49=0
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  5. #5
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    Quote Originally Posted by greenpumpkins View Post
    5x^2+28x-49

    What are the solutions? and how do I find them
    <br />
5x^2 + 28x - 49 = 0<br />

    <br />
a = 5<br />
    <br />
b = 28<br />
    <br />
c = 49<br />

     x_{1,2} = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}<br />
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