1. ## Finding Solutions?

5x^2+28x-49

What are the solutions? and how do I find them

2. Originally Posted by greenpumpkins
5x^2+28x-49

What are the solutions? and how do I find them
There is no equation => no solution

If the equation is $\displaystyle 5x^2+28x-49=0$ then you can use the formula

$\displaystyle x = \frac{-14 \pm 21}{5}$

$\displaystyle x_1 = -7$ and $\displaystyle x_2 = \frac{7}{5}$

3. Originally Posted by running-gag
There is no equation => no solution

If the equation is $\displaystyle 5x^2+28x-49=0$ then you can use the formula

$\displaystyle x = \frac{-14 \pm 21}{5}$

$\displaystyle x_1 = -7$ and $\displaystyle x_2 = \frac{7}{5}$
Uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly NOT 0!
Where did you get that formula?

4. Originally Posted by hallsofivy
uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly not 0!
Where did you get that formula?
$\displaystyle 5(49)+28(-7)-49= 245-196-49=0$

5. Originally Posted by greenpumpkins
5x^2+28x-49

What are the solutions? and how do I find them
$\displaystyle 5x^2 + 28x - 49 = 0$

$\displaystyle a = 5$
$\displaystyle b = 28$
$\displaystyle c = 49$

$\displaystyle x_{1,2} = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}$