5x^2+28x-49 What are the solutions? and how do I find them
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Originally Posted by greenpumpkins 5x^2+28x-49 What are the solutions? and how do I find them There is no equation => no solution If the equation is $\displaystyle 5x^2+28x-49=0$ then you can use the formula $\displaystyle x = \frac{-14 \pm 21}{5}$ $\displaystyle x_1 = -7$ and $\displaystyle x_2 = \frac{7}{5}$
Originally Posted by running-gag There is no equation => no solution If the equation is $\displaystyle 5x^2+28x-49=0$ then you can use the formula $\displaystyle x = \frac{-14 \pm 21}{5}$ $\displaystyle x_1 = -7$ and $\displaystyle x_2 = \frac{7}{5}$ Uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly NOT 0! Where did you get that formula?
Originally Posted by hallsofivy uhh, running-gag, 5(49)+ 28(7)- 49= 245+ 196- 49 is certainly not 0! Where did you get that formula? $\displaystyle 5(49)+28(-7)-49= 245-196-49=0$
Originally Posted by greenpumpkins 5x^2+28x-49 What are the solutions? and how do I find them $\displaystyle 5x^2 + 28x - 49 = 0 $ $\displaystyle a = 5 $ $\displaystyle b = 28 $ $\displaystyle c = 49 $ $\displaystyle x_{1,2} = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a} $
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