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Math Help - How do I do this problem please?

  1. #1
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    How do I do this problem please?



    I understand that A = 22/7

    I don't know how to work out the rest. For example is B worked out like this.
    3 + 1 = 4/1
    7+ 1/15 = 106/15

    So I then have 4/1 and 106/15 - what do I do next or have I gone wrong already ?
    Can anyone help me please?
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  2. #2
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    Hi

    B = 3 + \frac{1}{7+\frac{1}{15}}

    B = 3 + \frac{1}{\frac{7 \cdot 15+1}{15}}

    B = 3 + \frac{1}{\frac{106}{15}}

    B = 3 + \frac{15}{106}

    B = \frac{3\cdot 106+15}{106}

    B = \frac{333}{106}
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  3. #3
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    <br />
3 + \frac {1}{7} = \frac {21}{7} + \frac{1}{7} = \frac {22}{7}<br />

     3 + \frac {1}{7+ \frac {1}{15}} = 3 + \frac {1}{\frac {106}{15}} = 3 + \frac {15}{106} = \frac {318}{106} + \frac {15}{306} = \frac {333}{106}<br />

    another example..

    <br />
\frac{\frac{4}{3}}{\frac{5}{2}} = \frac {4 \times 2} {5 \times 3}<br />

    do you undestand now?
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  4. #4
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    Thank you.
    I am going to print that off and try and do the rest and I'll come back a little more later with my (hopefully correct ) answers.
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  5. #5
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    This is my answer to C.


    15 X 1 +1 = 16
    1

    7 x 16 + 1 = 7x16 = 112+1 = 113
    16 16

    3 x 113+16 = 139 + 16 = 155
    16 113

    C= 155/113
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  6. #6
    MHF Contributor
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    Quote Originally Posted by reallystuck View Post
    This is my answer to C.


    15 X 1 +1 = 16
    1

    7 x 16 + 1 = 7x16 = 112+1 = 113
    16 16

    3 x 113+16 = 339 + 16 = 355
    16 113

    C= 355/113
    I have corrected in red
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  7. #7
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    Sorry that was a typo.
    So apart from that mistake it was right ?

    I'll try the last one now.

    Thanks again
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