if , find the value of in terms of p.
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Hello, Originally Posted by requal if , find the value of in terms of p. Better now ? Otherwise, you could write and just substitute. There would have been a common factor :
Hello, requal! Another approach . . . We have: . .[1] Add 1 to both sides of [1]: . . . and we have: . .[2] Subtract 1 from both sides of [1]: . . . and we have: . .[3] Divide [2] by [3]: .
It's pretty equivalent Maybe yours can still be simplified. Originally Posted by Soroban . . and we have: . .[2] Just keep . . and we have: . .[3] Keep Dividing the two equations, we directly find The problem is that maybe one can't see why we have to subtract/add 1 to aČ/bČ
Originally Posted by Moo Hello, Better now ? Sorry to bump this thread but I don't follow? I was thinking you were trying to make it into 1+p/1-p but its thats in the form of 1+p/p+1?
Originally Posted by Soroban Hello, requal! Another approach . . . We have: . .[1] Add 1 to both sides of [1]: . . . and we have: . .[2] Subtract 1 from both sides of [1]: . . . and we have: . .[3] Divide [2] by [3]: . Is there some special reason that you would add/subtract one from both equations? Or is it just to make it easier to do
Originally Posted by Moo Hello, Better now ? Originally Posted by requal Sorry to bump this thread but I don't follow? I was thinking you were trying to make it into 1+p/1-p but its thats in the form of 1+p/p+1? It is not bumping when you ask a follow-up question. Follow-up questions are always welcome and encouraged. Substitute into .
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