Simplify 4^(2log(base8)7) into the form a^(b/c), all integers.

Could someone point me in the right direction?

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- Feb 21st 2009, 09:23 PMjsmith902104^(2log(base8)7), equivalent expression, integers
Simplify 4^(2log(base8)7) into the form a^(b/c), all integers.

Could someone point me in the right direction? - Feb 21st 2009, 11:25 PMInvertible
- Feb 22nd 2009, 12:40 AMearboth
- Feb 22nd 2009, 12:49 AMInvertible
- Feb 22nd 2009, 02:39 PMjsmith90210
what is the name of that rule?

- Feb 22nd 2009, 03:10 PMSoroban
Hello, jsmith90210!

A different approach . . .

Quote:

Simplify into the form , all integers.

We have: . .[1]

Let

. . Then: .

. . Hence: .

Substitute into [1]: .

. . . . .

This answer is correct ... it satisfies the requirements of the problem.

But I bet that "they" simplified it further: .