Real Roots

**Aminekhadir** · February 21st 2009, 12:11 PM

Hi! I've tried to solve this question, but I came to the conclusion that I couldn't so I gave up! I hope you can help me with this one

The equation x^2 - 2kx + 1 = 0 has two distinct real roots. Find the set of all possible values of k.

I would appreciate your help

Thanks,
Amine.

**running-gag** · February 21st 2009, 12:14 PM

Hi

The discriminant is $\Delta = (-2k)^2-4 = 4(k^2-1)$

The equation $x^2 - 2kx + 1 = 0$ has two distinct real roots if $\Delta > 0$

Can you go on ?

**Aminekhadir** · February 21st 2009, 12:22 PM

Does the final answer give 1/2(x + 1/x)?

**running-gag** · February 21st 2009, 12:30 PM

Originally Posted by Aminekhadir

Does the final answer give 1/2(x + 1/x)?

Not really
Don't forget you are asked to find a set of values of k

**Aminekhadir** · February 21st 2009, 12:33 PM

Ok, I will try to figure it out

Thanks for the help!

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