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Math Help - Find the sum or difference in the lowest term?

  1. #1
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    Find the sum or difference in the lowest term?

    1)  \frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}

    Attempt:
     \frac{a^4-a^3+2a^5+a^6}{a^6}

    Is my attempt CORRECT please check it but if not please write your answers in steps...

    Thank you for your help and for taking the time to read my question
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  2. #2
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    Quote Originally Posted by mj.alawami View Post
    1)  \frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}

    Attempt:
     \frac{a^4-a^3+2a^5+a^6}{a^6}

    Is my attempt CORRECT please check it but if not please write your answers in steps...

    Thank you for your help and for taking the time to read my question
    a^3 is the LCD ...

     \frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}

     \frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}

    \frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =

    \frac{a+1-a^2-2a+a^3+3a^2}{a^3} =

    \frac{a^3+2a^2-a+1}{a^3}
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  3. #3
    Like a stone-audioslave ADARSH's Avatar
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    Just a little more

    = \frac{a^3(a -1+2a^2 + a^3 )}{a^3 \times a^3}

     <br />
=\frac{(a -1+2a^2 + a^3 )}{a^3}<br />
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  4. #4
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    Quote Originally Posted by skeeter View Post
    a^3 is the LCD ...

     \frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}

     \frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}

    \frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =

    \frac{a+1-a^2-2a+a^3+3a^2}{a^3} =

    \frac{a^3+2a^2-a+1}{a^3}
    Thanks aloots
    Last edited by mr fantastic; February 21st 2009 at 01:01 PM.
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