Find the sum or difference in the lowest term?

**mj.alawami** · February 21st 2009, 05:38 AM

1) $\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

Attempt:
$\frac{a^4-a^3+2a^5+a^6}{a^6}$

Is my attempt CORRECT please check it but if not please write your answers in steps...

Thank you for your help and for taking the time to read my question

**skeeter** · February 21st 2009, 05:45 AM

Originally Posted by mj.alawami

1) $\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

Attempt:
$\frac{a^4-a^3+2a^5+a^6}{a^6}$

Is my attempt CORRECT please check it but if not please write your answers in steps...

Thank you for your help and for taking the time to read my question

$a^3$ is the LCD ...

$\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

$\frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}$

$\frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =$

$\frac{a+1-a^2-2a+a^3+3a^2}{a^3} =$

$\frac{a^3+2a^2-a+1}{a^3}$

**ADARSH** · February 21st 2009, 05:47 AM

Just a little more

$= \frac{a^3(a -1+2a^2 + a^3 )}{a^3 \times a^3}$

$<br /> =\frac{(a -1+2a^2 + a^3 )}{a^3}<br />$

**mj.alawami** · February 21st 2009, 06:01 AM

Originally Posted by skeeter

$a^3$ is the LCD ...

$\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

$\frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}$

$\frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =$

$\frac{a+1-a^2-2a+a^3+3a^2}{a^3} =$

$\frac{a^3+2a^2-a+1}{a^3}$

Thanks aloots

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