Find the sum or difference in the lowest term?

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February 21st 2009, 05:38 AM
mj.alawami

Find the sum or difference in the lowest term?

1) $\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

Attempt:
$\frac{a^4-a^3+2a^5+a^6}{a^6}$

Is my attempt CORRECT please check it but if not please write your answers in steps...

Thank you for your help and for taking the time to read my question (Happy)
February 21st 2009, 05:45 AM
skeeter

Quote:

Originally Posted by mj.alawami

1) $\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

Attempt:
$\frac{a^4-a^3+2a^5+a^6}{a^6}$

Is my attempt CORRECT please check it but if not please write your answers in steps...

Thank you for your help and for taking the time to read my question (Happy)

$a^3$ is the LCD ...

$\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

$\frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}$

$\frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =$

$\frac{a+1-a^2-2a+a^3+3a^2}{a^3} =$

$\frac{a^3+2a^2-a+1}{a^3}$
February 21st 2009, 05:47 AM
ADARSH

http://www.mathhelpforum.com/math-he...8674cee3-1.gif

Just a little more

$= \frac{a^3(a -1+2a^2 + a^3 )}{a^3 \times a^3}$

$<br /> =\frac{(a -1+2a^2 + a^3 )}{a^3}<br />$
(Nod)
February 21st 2009, 06:01 AM
mj.alawami

Quote:

Originally Posted by skeeter

$a^3$ is the LCD ...

$\frac{a+1}{a^3} - \frac{a+2}{a^2} +\frac{a+3}{a}$

$\frac{a+1}{a^3} - \frac{a(a+2)}{a^3} +\frac{a^2(a+3)}{a^3}$

$\frac{(a+1)-a(a+2)+a^2(a+3)}{a^3} =$

$\frac{a+1-a^2-2a+a^3+3a^2}{a^3} =$

$\frac{a^3+2a^2-a+1}{a^3}$

Thanks aloots (Clapping)

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