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Math Help - Combination equations

  1. #1
    Newbie
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    Feb 2009
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    5

    Combination equations

    Hey, thanks for reading this. I'm having trouble with a particular problem, and it goes:

    The number of arrangements of 2n+2 different objects taken n at a time is to the number of arrangements of 2n different objects taken n at a time as 14:5. Find the value of n.

    For this I gather that:

    arrangements of 2n+2 objects : arrangements of 2n objects = 14:5

    However, I don't understand the taken n at a time part...does that mean 2n+2 objects arranged in n spaces?

    If so, would that be the same as saying:

    (2n+2)! / (2n+2-n)! : (2n)! / (2n-n)! = 14:5

    I've also thought about simplify it to (2n+2)(2n+1)(2n)! / (2n+2-r)(2n+1-r)(2n-r)! so to make it similar to the RHS.

    Ayy input or insight would be sincerely appriciated.

    Thanks!

    -EDIT- Don't worry, after a bit of re-reading, I figured it out.
    Last edited by Khorne; February 21st 2009 at 01:11 AM.
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