Is this right? Graphing an Equation

• Feb 20th 2009, 02:24 PM
BeachLover
Is this right? Graphing an Equation
I have a fairly good concept of how to solve for y, at least I think I do.
I have this equation and I would like to know if I solved it correctly.
Thank you for any help, I have rarely seen the y like this.

y-3x= -2 and 6x-2y= 4
I am supposed to graph these and then determine if they are parallel, intersect, or if they are the same line.

I have this:

y=3x-2 and y= -3x-2
I have determined that they do intersect, and meet at the point (0,-2)
Is this right?

Thanks,
Anna
• Feb 20th 2009, 02:32 PM
Air
Quote:

Originally Posted by BeachLover
I have a fairly good concept of how to solve for y, at least I think I do.
I have this equation and I would like to know if I solved it correctly.
Thank you for any help, I have rarely seen the y like this.

y-3x= -2 and 6x-2y= 4
I am supposed to graph these and then determine if they are parallel, intersect, or if they are the same line.

I have this:

y=3x-2 and y= -3x-2
I have determined that they do intersect, and meet at the point (0,-2)
Is this right?

Thanks,
Anna

An equation for the linear line is \$\displaystyle y=mx+c\$ where \$\displaystyle y,x\$ are the variables, \$\displaystyle m\$ is the gradient (slope) and \$\displaystyle c\$ is the \$\displaystyle y\$-intercept (where it crosses \$\displaystyle y\$-axis).

\$\displaystyle y-3x=-2\$
\$\displaystyle y = 3x-2\$ Which is the solution that you got. (Clapping)

\$\displaystyle 6x-2y= 4\$
\$\displaystyle -2y=4-6x\$
\$\displaystyle y=3x-2\$ You had a sign error here.

Both lines are the same, with a gradient of \$\displaystyle 3\$ and a y-intercept of \$\displaystyle -2\$.
• Feb 20th 2009, 02:41 PM
BeachLover
AH!!
I see where I messed up.
Thank you so much!!