y=3x-1/2x My attempt: x= ( I get stuck her what do l do with the y in the denominator ? )
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Once you have that 2yx= 6y^2- 1, rewrite it as 6y^2- 2xy- 1 and use the quadratic formula to solve for y. Solve that quadratic equation for x you will get a " ". This function does not have a true inverse.
Originally Posted by HallsofIvy Once you have that 2yx= 6y^2- 1, rewrite it as 6y^2- 2xy- 1 and use the quadratic formula to solve for y. Solve that quadratic equation for x you will get a " ". This function does not have a true inverse. I solved it thank you very much for your help
Originally Posted by HallsofIvy Once you have that 2yx= 6y^2- 1, rewrite it as 6y^2- 2xy- 1 and use the quadratic formula to solve for y. Solve that quadratic equation for x you will get a " ". This function does not have a true inverse. If my restricted domain is D={x|x<0} does that mean for my inverse function is going to be the one with a minus sign on the quadratic equation.
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