2nd Algebraic Fraction question

**NathanielFisher** · February 19th 2009, 10:57 AM

2k-3 - 3k + 1
____ ____
6 8

The answer is :

- (k +15)
________
24

I'm not sure how to get to the answer after many retries.

**masters** · February 19th 2009, 11:44 AM

Originally Posted by NathanielFisher

2k-3 - 3k + 1
____ ____
6 8

The answer is :

- (k +15)
________
24

I'm not sure how to get to the answer after many retries.

Hi Nathaniel,

$\frac{2k-3}{6}-\frac{3k+1}{8}$

The GCF is 24.

Multiply each term by 24 and place the result over 24.

$\frac{24\left(\frac{2k-3}{6}\right)-24\left(\frac{3k+1}{8}\right)}{24}$

$\frac{4(2k-3)-3(3k+1)}{24}$

$\frac{8k-12-9k-3}{24}$

$\frac{-k-15}{24}$

$\frac{-(k+15)}{24}$

**NathanielFisher** · February 19th 2009, 03:02 PM

Thanks for the help.

What I was doing was:

-3 x +1 = + 3 :|

+ and - = -

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