I think that I did this one correctly as well but I could not figure out the factoring.
√x+2 + √3x+7=1
√3x+7 = 1-√x+2
√(3x+7)^2 =(1-√x+2)^2
3x+7=1-x = 2-2√x+2
3x+7 = -x+3-2√x+2
2x +4 = (-2√x+2)
(2x+4)^2= (2√x+2)^2
4x^2+16x+16=4(x+2)
4x^2+12x-8=0
I think that I did this one correctly as well but I could not figure out the factoring.
√x+2 + √3x+7=1
√3x+7 = 1-√x+2
√(3x+7)^2 =(1-√x+2)^2
3x+7=1-x = 2-2√x+2
3x+7 = -x+3-2√x+2
2x +4 = (-2√x+2)
(2x+4)^2= (2√x+2)^2
4x^2+16x+16=4(x+2)
4x^2+12x-8=0