I'm stumped on this one problem...

Bob has $4.95 in quarters and dimes. He has 3 times as many dimes as quarters.

I don't get how to set this up. (Sleepy)

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- Feb 18th 2009, 03:13 PMJubblySystem of equation
I'm stumped on this one problem...

Bob has $4.95 in quarters and dimes. He has 3 times as many dimes as quarters.

I don't get how to set this up. (Sleepy) - Feb 18th 2009, 03:24 PMwilsoac
x=quarters

3x=dimes

4.95=total

so you take the worth of the coins times the amount, add them together for the total.

3x(.10)+.25x=4.95

.30x+.25x=4.95

.55x=4.95

.55x/.55=4.95/.55

x=9 (quarters)

3x=27 (dimes)

check your answer:

9 quarters equals $2.25

27 dimes equals $2.70

add them together and you get $4.95 - Feb 18th 2009, 03:35 PMJubbly
Thanks so much!