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Thread: factoring finding zeroes

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    factoring finding zeroes

    can someone help me find the zeroes of this equation?

    5x^2-11x+4
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    Quote Originally Posted by runner940 View Post
    can someone help me find the zeroes of this equation?

    5x^2-11x+4
    quadratic formula ...

    b^2 - 4ac = 121 - 80 = 41

    x = \frac{11 \pm \sqrt{41}}{10}
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