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can someone help me find the zeroes of this equation? 5x^2-11x+4

Quote: Originally Posted by runner940 can someone help me find the zeroes of this equation? 5x^2-11x+4 quadratic formula ... $\displaystyle b^2 - 4ac = 121 - 80 = 41$ $\displaystyle x = \frac{11 \pm \sqrt{41}}{10}$