2x+3/5=9
-30=2x^-1
32=4/6x-34
4x-5x=3-5+6x
Is this
$\displaystyle 32 = \frac{4}{6x} - 34$
or
$\displaystyle 32 = \frac{4}{6x-34}$
I'm going to guess it is the second one.
$\displaystyle 32 = \frac{4}{6x-34}$
$\displaystyle 30 \cdot (6x-34) = \frac{4}{6x-34} \cdot (6x-34)$
$\displaystyle 30(6x-34) = 4$
$\displaystyle 180x - 1020 = 4$
$\displaystyle 180x - 1020 + 1020 = 4 + 1020$
$\displaystyle 180x = 1024$
$\displaystyle \frac{180x}{180} = \frac{1024}{180}$
$\displaystyle x = \frac{256}{45}$
-Dan
What is this? Is it
$\displaystyle \frac{2x+3}{5} = 9$?
If so:
$\displaystyle \frac{2x+3}{5} \cdot 5 = 9 \cdot 5$
$\displaystyle 2x + 3 = 45$
$\displaystyle 2x + 3 - 3 = 45 - 3$
$\displaystyle 2x = 42$
$\displaystyle \frac{2x}{2} = \frac{42}{2}$
$\displaystyle x = 21$
-Dan