I can't figure this out.. is it unsolvable? $\displaystyle 3y^2 - 6xy + 3x^2 - 3 = 0$ Solve for either x or y Thanks
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Originally Posted by DHS1 I can't figure this out.. is it unsolvable? $\displaystyle 3y^2 - 6xy + 3x^2 - 3 = 0$ Solve for either x or y Thanks Reduce the equation to : $\displaystyle y^2-2xy+x^2-1=0$ $\displaystyle (y-x)^2=1$ Thus , y-x=1 or y-x=-1
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