
Simplification
This is the original formula:
$\displaystyle p(\frac{p}{3w_1})^\frac{1}{2}x^\frac{1}{2}_2w_1(\frac{p}{3w_1})^\frac{3}{2}x^\frac{1}{2}_2w_2x_2$
This is how far I've gotten:
$\displaystyle \frac{2p}{3}(\frac{p}{3w_1})^\frac{1}{2}x^\frac{1} {2}_{2}w_2x_2$
And this is the final answer I need to get to:
$\displaystyle (\frac{4p^3}{27w_1})^\frac{1}{2}x^\frac{1}{2}_2w_2x_2$
Any help would be greatly appreciated, thank you!

All you need to do is get the outer 2p/3 rewritten as
$\displaystyle \sqrt{(4p^2/9)}$
Then it would have the same power as the other item raised to the 1/2 power so they could combine.