# Simplification

• Feb 16th 2009, 03:06 PM
waffles247
Simplification
This is the original formula:
$p(\frac{p}{3w_1})^\frac{1}{2}x^\frac{1}{2}_2-w_1(\frac{p}{3w_1})^\frac{3}{2}x^\frac{1}{2}_2-w_2x_2$

This is how far I've gotten:
$\frac{2p}{3}(\frac{p}{3w_1})^\frac{1}{2}x^\frac{1} {2}_{2}-w_2x_2$

And this is the final answer I need to get to:
$(\frac{4p^3}{27w_1})^\frac{1}{2}x^\frac{1}{2}_2-w_2x_2$

Any help would be greatly appreciated, thank you!
• Feb 16th 2009, 03:20 PM
wytiaz
All you need to do is get the outer 2p/3 rewritten as

$\sqrt{(4p^2/9)}$

Then it would have the same power as the other item raised to the 1/2 power so they could combine.