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Thread: Negative and zero exponets

  1. #1
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    Negative and zero exponets

    My teacher assigned me this assignment and it looks totally different that what we did... here are a few of the problems...

    X^-2 Y^4

    C^0 D^4

    R^-3 T^5

    There is just a couple of them I just want to get the hang of it so I can do the rest.
    P.S I made this thread in the exponents section but i realized that there is this section... I believe it would be better because it is really urgent.
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    Quote Originally Posted by XGBrandon View Post
    My teacher assigned me this assignment and it looks totally different that what we did... here are a few of the problems...

    X^-2 Y^4

    C^0 D^4

    R^-3 T^5

    There is just a couple of them I just want to get the hang of it so I can do the rest.
    P.S I made this thread in the exponents section but i realized that there is this section... I believe it would be better because it is really urgent.
    Hi XGBrandon,

    What were your instructions? Simplify? Get rid of negative exponents?

    $\displaystyle x^{-2}y^4=\frac{y^4}{x^2}$

    $\displaystyle c^0d^4=1d^4=d^4$

    $\displaystyle r^{-3}t^5=\frac{t^5}{r^3}$
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    Quote Originally Posted by masters View Post
    Hi XGBrandon,

    What were your instructions? Simplify? Get rid of negative exponents?

    $\displaystyle x^{-2}y^4=\frac{y^4}{x^2}$

    $\displaystyle c^0d^4=1d^4=d^4$

    $\displaystyle r^{-3}t^5=\frac{t^5}{r^3}$
    get rid of the negative exponent and it has to be in fraction form.,
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    Also htis one is throwing me off...ab^0 c^-4 would it be c^4 ?
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    Quote Originally Posted by XGBrandon View Post
    get rid of the negative exponent and it has to be in fraction form.,
    Ok then. That's what I thought. All are in fraction form except $\displaystyle d^4$. If you wanted to, I guess you could write it as $\displaystyle \frac{d^4}{1}$, but I don't know why you would want to.
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    Quote Originally Posted by masters View Post
    Ok then. That's what I thought. All are in fraction form except $\displaystyle d^4$. If you wanted to, I guess you could write it as $\displaystyle \frac{d^4}{1}$, but I don't know why you would want to.
    Do you got a instant messenger program?
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    Quote Originally Posted by XGBrandon View Post
    Also htis one is throwing me off...ab^0 c^-4 would it be c^4 ?
    $\displaystyle ab^0c^{-4}=\frac{a}{c^4}$

    The variable a remains in the numerator. $\displaystyle c^{-4}$ must go to the denominator to have a positive exponent. $\displaystyle b^0$ is simply 1.
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    another problem I came across is g^7 h^-1 k
    would the answer be K/GH ?
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    Quote Originally Posted by XGBrandon View Post
    another problem I came across is g^.7 h^-1 k
    would the answer be K/GH ?
    This one looks a little strange. Is it copied correctly? If so, then

    $\displaystyle g^{.7}h^{-1}k=\frac{g^{.7}k}{h} \ \ or \ \ \frac{g^{7/10}k}{h}$

    The g and the k term stay in the numerator. The h term moves to the denominator to achieve a positive exponent of 1.

    Remember a few rules:

    $\displaystyle a^0=1$

    $\displaystyle a^{-1}=\frac{1}{a}$

    $\displaystyle a^{-n}=\frac{1}{a^n}$
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    Masters, I don't see any decimal 7 in the problem. I see g^7 h^-1 k.

    XGBrandon, you have been told, repeatedly, that the negative exponent means it goes into the denominator (with positive exponent). Only the h has a negative exponent. And the "7" exponent on the g doesn't just "disappear".

    $\displaystyle g^7h^{-1}k= \frac{gk}{h}$
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    Quote Originally Posted by HallsofIvy View Post
    Masters, I don't see any decimal 7 in the problem. I see g^7 h^-1 k.

    XGBrandon, you have been told, repeatedly, that the negative exponent means it goes into the denominator (with positive exponent). Only the h has a negative exponent. And the "7" exponent on the g doesn't just "disappear".

    $\displaystyle g^7h^{-1}k= \frac{gk}{h}$
    Hi HallsofIvy,

    I don't know where that decimal point came from. I just quoted XGB's post and there it was. Made it interesting, though. Spooky!
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