2√3 √5+2 √6 Soorry about not using latex buh i need help again...
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$\displaystyle \frac{2\sqrt{3}}{\sqrt{5}+2\sqrt{6}}$ The conjugate of a+b is simply a-b. What's nice about this product is you will get a^2-b^2, which eliminates square roots. Multiply the numerator and denominator by the conjugate of the denominator.
could u please show me the working to it so, express with rational denominator thanks
Originally Posted by salam could u please show me the working to it so, express with rational denominator thanks $\displaystyle \frac{2\sqrt{3}}{\sqrt{5}+2\sqrt{6}} \times \frac{\sqrt{5}-2\sqrt{6}}{\sqrt{5}-2\sqrt{6}}$ Like I said $\displaystyle (a+b)(a-b)=a^2-b^2$. What a and b are should be obvious. Take it from here.
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