1. ## help solve

if 1/a + 1/b = 3/8 and a*b = 3,

then find a+b and a^2 + b^2

HELP??

2. Originally Posted by Mr_Green
if 1/a + 1/b = 3/8 and a*b = 3,

then find a+b and a^2 + b^2

HELP??
First:

$
\frac{1}{a}+\frac{1}{b}=\frac{b+a}{ab}=\frac{a+b}{ 3}=\frac{3}{8}
$

Hence:

$a+b=\frac{9}{8}$

Second:

$(a+b)^2=a^2+b^2+2ab=(a^2+b^2)+6$

rearranging:

$
a^2+b^2=6-(a+b)^2=6-\left[\frac{9}{8}\right]^2=\frac{303}{64}
$

RonL