equation: (w+5)(6w^2-18)=0 I know one zero equals -5, can you help me find the other?
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Originally Posted by runner940 equation: (w+5)(6w^2-18)=0 I know one zero equals -5, can you help me find the other? $\displaystyle (w + 5) \cdot 6(w^2 - 3) = 0 \Rightarrow 6 (w + 5)(w - \sqrt{3})(w + \sqrt{3}) = 0 \, ....$
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