Hi, I need some help setting up this problem properly

Problem:

After 23 days a 10-milligram sample of radioactive material decays to 5 milligrams. After how many days will there be 1 milligram of the material?

thanks!

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- Nov 8th 2006, 09:31 AMdibsHelp with setting up a problem
Hi, I need some help setting up this problem properly

Problem:

After 23 days a 10-milligram sample of radioactive material decays to 5 milligrams. After how many days will there be 1 milligram of the material?

thanks! - Nov 8th 2006, 09:50 AMtopsquark
$\displaystyle m(t) = m_0 e^{- \lambda t}$ where m(t) is the mass of the material at a given time t, $\displaystyle m_0$ is the initial amount of mass m(0), $\displaystyle \lambda$ is the half-life, and t is the time elapsed.

So we know that

$\displaystyle 5 = 10 e^{- \lambda \cdot 23}$

We need to solve this for $\displaystyle \lambda$.

$\displaystyle \frac{1}{2} = e^{-23 \lambda}$

$\displaystyle ln (1/2) = -23 \lambda$

$\displaystyle \lambda = -\frac{ln(1/2)}{23} = \frac{ln(2)}{23} \approx 0.030136834$ /day

So

$\displaystyle m(t) = 10 e^{-0.030136834 t}$

We wish to find out when m(t) = 1 mg.

$\displaystyle 1 = 10 e^{-0.030136834 t}$

Solve this like the preceding problem. I get $\displaystyle t \approx 76.404346182$ days.

So 76.4 days or so.

-Dan - Nov 8th 2006, 11:00 AMdibs
thank you very much for the help!