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Math Help - simplify:

  1. #1
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    simplify:

    simplify:


    3/i + 6/(i+2) + i/(i-2)
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Mr_Green View Post
    simplify:


    3/i + 6/(i+2) + i/(i-2)
    i is a square root. Thus we wish to get rid of the square roots in the denominators. You do this by multiplying the denominator by the complex conjugate of the denominator.

    For example:
    \frac{6}{i+2} = \frac{6}{i+2} \cdot \frac{-i + 2}{-i + 2}

    = \frac{6(-i+2)}{-i^2 + 4} = \frac{12 - 6i}{1+4} = \frac{12-6i}{5}

    Can you take it from here?

    -Dan
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  3. #3
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    Unhappy

    Quote Originally Posted by topsquark View Post
    i is a square root. Thus we wish to get rid of the square roots in the denominators. You do this by multiplying the denominator by the complex conjugate of the denominator.

    For example:
    \frac{6}{i+2} = \frac{6}{i+2} \cdot \frac{-i + 2}{-i + 2}

    = \frac{6(-i+2)}{-i^2 + 4} = \frac{12 - 6i}{1+4} = \frac{12-6i}{5}

    Can you take it from here?

    -Dan
    I'm still stuck! Please help
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  4. #4
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    Well he did one of the terms. Are you paying attention to his method? The method is the key.

    \frac{3}{i} \times \frac{i}{i}=-3i

    \frac{i}{i-2} \times \frac{i+2}{i+2}=...
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