Can someone explain to me how to convert standard form to slope-intercept form and vice-versa? Thanks.
One of my problems is: "Convert 3x+4y=12 to slope-intercept form".
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Can someone explain to me how to convert standard form to slope-intercept form and vice-versa? Thanks.
One of my problems is: "Convert 3x+4y=12 to slope-intercept form".
Standard form of a line equation is:Quote:
Originally Posted by FlareHazard
Ax + By = C ,
For your problem:
3x + 4y = 12 is in standard form.
To put it into slope-intercept form, y= mx +b, just solve the equation for y.
y = mx + b, where m is your slope and b is your y intercept.
To go from slope-intercept to standard form, you just need to get x & y on the same side. Do this by subtracting your mx term.